What are the solutions to the equation 5-4x^2=-19 ?

The solutions to the equation 5-4x^2=-19 are x=sqrt(6),x=-sqrt(6)

Find the zeros of 5-4x^2=-19

The zeros of 5-4x^2=-19 are x=sqrt(6),x=-sqrt(6)

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5 - 4 x^{2} = - 19

x = 6, x = - 6

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots

Solution steps

5 - 4 x^{2} = - 19

Move

5

to the right side

- 4 x^{2} = - 24

Divide both sides by

- 4

x^{2} = 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 6, x = - 6

x^{2} = - x^{2} + 18 x

0 = 12 x^{2} - 48 x + 36

6 x^{2} - 7 x = 0

y^{2} + 5 y - 36 = 0

(x + 1) (x + 5) = 32

What are the solutions to the equation 5-4x^2=-19 ?
The solutions to the equation 5-4x^2=-19 are x=sqrt(6),x=-sqrt(6)
Find the zeros of 5-4x^2=-19
The zeros of 5-4x^2=-19 are x=sqrt(6),x=-sqrt(6)