What are the solutions to the equation 5x^2+2x-39=0 ?

The solutions to the equation 5x^2+2x-39=0 are x= 13/5 ,x=-3

Find the zeros of 5x^2+2x-39=0

The zeros of 5x^2+2x-39=0 are x= 13/5 ,x=-3

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5 x^{2} + 2 x - 39 = 0

x = \frac{13}{5}, x = - 3

Decimal Notation

x = 2.6, x = - 3

Solution steps

5 x^{2} + 2 x - 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 ( - 39 )}{2 \cdot 5}

2^{2} - 4 \cdot 5 (- 39) = 28

x_{1, 2} = \frac{- 2 \pm 28}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 2 + 28}{2 \cdot 5}, x_{2} = \frac{- 2 - 28}{2 \cdot 5}

x = \frac{- 2 + 28}{2 \cdot 5} : \frac{13}{5}

x = \frac{- 2 - 28}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = \frac{13}{5}, x = - 3

h, 0 = \frac{π R ^{2} - 3 π h ^{2}}{4}

(s^{2} + 4) = 0

0 = - 16 x^{2} + 144 x + 5000

3 x - 2 = - 20 x^{2}

3 x^{2} + 12 = 7 x + 32

What are the solutions to the equation 5x^2+2x-39=0 ?
The solutions to the equation 5x^2+2x-39=0 are x= 13/5 ,x=-3
Find the zeros of 5x^2+2x-39=0
The zeros of 5x^2+2x-39=0 are x= 13/5 ,x=-3