What are the solutions to the equation 3((x+2)^2-7-8/3)=0 ?

The solutions to the equation 3((x+2)^2-7-8/3)=0 are x=sqrt(29/3)-2,x=-sqrt(29/3)-2

Find the zeros of 3((x+2)^2-7-8/3)=0

The zeros of 3((x+2)^2-7-8/3)=0 are x=sqrt(29/3)-2,x=-sqrt(29/3)-2

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3 ((x + 2)^{2} - 7 - \frac{8}{3}) = 0

x = \frac{29}{3} - 2, x = - \frac{29}{3} - 2

Decimal Notation

x = 1.10912 \dots, x = - 5.10912 \dots

Solution steps

3 ((x + 2)^{2} - 7 - \frac{8}{3}) = 0

Divide both sides by

3

(x + 2)^{2} - \frac{29}{3} = 0

Move

\frac{29}{3}

to the right side

(x + 2)^{2} = \frac{29}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = \frac{29}{3} : x = \frac{29}{3} - 2

Solve

x + 2 = - \frac{29}{3} : x = - \frac{29}{3} - 2

The solutions to the quadratic equation are:

x = \frac{29}{3} - 2, x = - \frac{29}{3} - 2

x^{2} = 1 - 8 x

2 - x^{2} = x^{2} - 16

x, - 9 x^{2} - 9 y^{2} + z^{2} + 6 z + 18 = 0

x^{2} = \frac{- 1}{- 9}

6 x^{2} + 144 = 0

What are the solutions to the equation 3((x+2)^2-7-8/3)=0 ?
The solutions to the equation 3((x+2)^2-7-8/3)=0 are x=sqrt(29/3)-2,x=-sqrt(29/3)-2
Find the zeros of 3((x+2)^2-7-8/3)=0
The zeros of 3((x+2)^2-7-8/3)=0 are x=sqrt(29/3)-2,x=-sqrt(29/3)-2