What are the solutions to the equation 0=-6+8x-5/2 x^2 ?

The solutions to the equation 0=-6+8x-5/2 x^2 are x= 6/5 ,x=2

Find the zeros of 0=-6+8x-5/2 x^2

The zeros of 0=-6+8x-5/2 x^2 are x= 6/5 ,x=2

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0 = - 6 + 8 x - \frac{5}{2} x^{2}

x = \frac{6}{5}, x = 2

Decimal Notation

x = 1.2, x = 2

Solution steps

0 = - 6 + 8 x - \frac{5}{2} x^{2}

Multiply both sides by

2

0 = - 12 + 16 x - 5 x^{2}

Switch sides

- 12 + 16 x - 5 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} + 16 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 5 ) ( - 12 )}{2 ( - 5 )}

1 6^{2} - 4 (- 5) (- 12) = 4

x_{1, 2} = \frac{- 16 \pm 4}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 16 + 4}{2 ( - 5 )}, x_{2} = \frac{- 16 - 4}{2 ( - 5 )}

x = \frac{- 16 + 4}{2 ( - 5 )} : \frac{6}{5}

x = \frac{- 16 - 4}{2 ( - 5 )} : 2

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = 2

x^{2} + 14 x = - 7

3 (x + 8)^{2} = 60

x, 4 x y - x^{2} - 3 x = 0

A (x) = x (\frac{126 - 2 x}{3})

7^{2} + 1 2^{2} = c^{2}

What are the solutions to the equation 0=-6+8x-5/2 x^2 ?
The solutions to the equation 0=-6+8x-5/2 x^2 are x= 6/5 ,x=2
Find the zeros of 0=-6+8x-5/2 x^2
The zeros of 0=-6+8x-5/2 x^2 are x= 6/5 ,x=2