What are the solutions to the equation x^2+5x-8=0 ?

The solutions to the equation x^2+5x-8=0 are x=(-5+sqrt(57))/2 ,x=(-5-sqrt(57))/2

Find the zeros of x^2+5x-8=0

The zeros of x^2+5x-8=0 are x=(-5+sqrt(57))/2 ,x=(-5-sqrt(57))/2

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x^{2} + 5 x - 8 = 0

x = \frac{- 5 + 57}{2}, x = \frac{- 5 - 57}{2}

Decimal Notation

x = 1.27491 \dots, x = - 6.27491 \dots

Solution steps

x^{2} + 5 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 8) = 57

x_{1, 2} = \frac{- 5 \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 57}{2 \cdot 1}, x_{2} = \frac{- 5 - 57}{2 \cdot 1}

x = \frac{- 5 + 57}{2 \cdot 1} : \frac{- 5 + 57}{2}

x = \frac{- 5 - 57}{2 \cdot 1} : \frac{- 5 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 57}{2}, x = \frac{- 5 - 57}{2}

5 x - 7 = 8

15 - 3 x = \frac{3}{28} x^{2} + \frac{9}{28} x

a^{2} + 7^{2} = 2 5^{2}

\frac{m + 3 m}{3} - 1 \leq 2

What are the solutions to the equation x^2+5x-8=0 ?
The solutions to the equation x^2+5x-8=0 are x=(-5+sqrt(57))/2 ,x=(-5-sqrt(57))/2
Find the zeros of x^2+5x-8=0
The zeros of x^2+5x-8=0 are x=(-5+sqrt(57))/2 ,x=(-5-sqrt(57))/2