What are the solutions to the equation 15-3x= 3/28 x^2+9/28 x ?

The solutions to the equation 15-3x= 3/28 x^2+9/28 x are x=4,x=-35

Find the zeros of 15-3x= 3/28 x^2+9/28 x

The zeros of 15-3x= 3/28 x^2+9/28 x are x=4,x=-35

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15 - 3 x = \frac{3}{28} x^{2} + \frac{9}{28} x

x = 4, x = - 35

Solution steps

15 - 3 x = \frac{3}{28} x^{2} + \frac{9}{28} x

Multiply both sides by

28

420 - 84 x = 3 x^{2} + 9 x

Switch sides

3 x^{2} + 9 x = 420 - 84 x

Move

84 x

to the left side

3 x^{2} + 93 x = 420

Move

420

to the left side

3 x^{2} + 93 x - 420 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 93 \pm 9 3 ^{2} - 4 \cdot 3 ( - 420 )}{2 \cdot 3}

9 3^{2} - 4 \cdot 3 (- 420) = 117

x_{1, 2} = \frac{- 93 \pm 117}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 93 + 117}{2 \cdot 3}, x_{2} = \frac{- 93 - 117}{2 \cdot 3}

x = \frac{- 93 + 117}{2 \cdot 3} : 4

x = \frac{- 93 - 117}{2 \cdot 3} : - 35

The solutions to the quadratic equation are:

x = 4, x = - 35

a^{2} + 7^{2} = 2 5^{2}

\frac{m + 3 m}{3} - 1 \leq 2

x^{2} - 8 x = 13

\frac{( 3 + i ) ^{10}}{1 + i}

What are the solutions to the equation 15-3x= 3/28 x^2+9/28 x ?
The solutions to the equation 15-3x= 3/28 x^2+9/28 x are x=4,x=-35
Find the zeros of 15-3x= 3/28 x^2+9/28 x
The zeros of 15-3x= 3/28 x^2+9/28 x are x=4,x=-35