What are the solutions to the equation (x+3)^2=17 ?

The solutions to the equation (x+3)^2=17 are x=sqrt(17)-3,x=-sqrt(17)-3

Find the zeros of (x+3)^2=17

The zeros of (x+3)^2=17 are x=sqrt(17)-3,x=-sqrt(17)-3

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(x + 3)^{2} = 17

x = 17 - 3, x = - 17 - 3

Decimal Notation

x = 1.12310 \dots, x = - 7.12310 \dots

Solution steps

(x + 3)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 17 : x = 17 - 3

Solve

x + 3 = - 17 : x = - 17 - 3

The solutions to the quadratic equation are:

x = 17 - 3, x = - 17 - 3

(x + 3)^{2} = 24

(x + 3)^{2} = 22

x, z^{2} = 2 z - x^{2} - y^{2}

0 = 3 x^{2} - 2 x - 20

x, (5 x + 3 y)^{2} = 5

What are the solutions to the equation (x+3)^2=17 ?
The solutions to the equation (x+3)^2=17 are x=sqrt(17)-3,x=-sqrt(17)-3
Find the zeros of (x+3)^2=17
The zeros of (x+3)^2=17 are x=sqrt(17)-3,x=-sqrt(17)-3