What are the solutions to the equation (x+3)^2=22 ?

The solutions to the equation (x+3)^2=22 are x=sqrt(22)-3,x=-sqrt(22)-3

Find the zeros of (x+3)^2=22

The zeros of (x+3)^2=22 are x=sqrt(22)-3,x=-sqrt(22)-3

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(x + 3)^{2} = 22

x = 22 - 3, x = - 22 - 3

Decimal Notation

x = 1.69041 \dots, x = - 7.69041 \dots

Solution steps

(x + 3)^{2} = 22

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 22 : x = 22 - 3

Solve

x + 3 = - 22 : x = - 22 - 3

The solutions to the quadratic equation are:

x = 22 - 3, x = - 22 - 3

x, z^{2} = 2 z - x^{2} - y^{2}

0 = 3 x^{2} - 2 x - 20

x, (5 x + 3 y)^{2} = 5

7 x^{2} - 5 x - 2 = - 1

4 x^{2} + 7 x = - 1

What are the solutions to the equation (x+3)^2=22 ?
The solutions to the equation (x+3)^2=22 are x=sqrt(22)-3,x=-sqrt(22)-3
Find the zeros of (x+3)^2=22
The zeros of (x+3)^2=22 are x=sqrt(22)-3,x=-sqrt(22)-3