What are the solutions to the equation 7x^2-5x-2=-1 ?

The solutions to the equation 7x^2-5x-2=-1 are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)

Find the zeros of 7x^2-5x-2=-1

The zeros of 7x^2-5x-2=-1 are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)

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7 x^{2} - 5 x - 2 = - 1

x = \frac{5 + 53}{14}, x = \frac{5 - 53}{14}

Decimal Notation

x = 0.87715 \dots, x = - 0.16286 \dots

Solution steps

7 x^{2} - 5 x - 2 = - 1

Move

1

to the left side

7 x^{2} - 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

(- 5)^{2} - 4 \cdot 7 (- 1) = 53

x_{1, 2} = \frac{- ( - 5 ) \pm 53}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 53}{2 \cdot 7}, x_{2} = \frac{- ( - 5 ) - 53}{2 \cdot 7}

x = \frac{- ( - 5 ) + 53}{2 \cdot 7} : \frac{5 + 53}{14}

x = \frac{- ( - 5 ) - 53}{2 \cdot 7} : \frac{5 - 53}{14}

The solutions to the quadratic equation are:

x = \frac{5 + 53}{14}, x = \frac{5 - 53}{14}

4 x^{2} + 7 x = - 1

2 x^{2} + 7 x - 14 = x^{2} + 4

2 x^{2} + 5 x = 6

x^{2} + 3 \cdot 1 0^{- 8} - 0.7 \cdot 1 0^{- 8} = 0

0 = 2 x^{2} - 2 x - 4

What are the solutions to the equation 7x^2-5x-2=-1 ?
The solutions to the equation 7x^2-5x-2=-1 are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)
Find the zeros of 7x^2-5x-2=-1
The zeros of 7x^2-5x-2=-1 are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)