What are the solutions to the equation 2x^2+x+15=0 ?

The solutions to the equation 2x^2+x+15=0 are x=-1/4+i(sqrt(119))/4 ,x=-1/4-i(sqrt(119))/4

Find the zeros of 2x^2+x+15=0

The zeros of 2x^2+x+15=0 are x=-1/4+i(sqrt(119))/4 ,x=-1/4-i(sqrt(119))/4

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2 x^{2} + x + 15 = 0

x = - \frac{1}{4} + i \frac{119}{4}, x = - \frac{1}{4} - i \frac{119}{4}

Solution steps

2 x^{2} + x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

Simplify

1^{2} - 4 \cdot 2 \cdot 15 : 119 i

x_{1, 2} = \frac{- 1 \pm 119 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 119 i}{2 \cdot 2}, x_{2} = \frac{- 1 - 119 i}{2 \cdot 2}

x = \frac{- 1 + 119 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{119}{4}

x = \frac{- 1 - 119 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{119}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{119}{4}, x = - \frac{1}{4} - i \frac{119}{4}

(\frac{5}{4})^{2} + y^{2} = 1

2 x^{2} + 3 x + 24 = 0

3 (x - 3) - 3 (x + 3) = (x + 3) (x - 3)

y, x^{2} y^{2} - 4 x^{2} - 4 y^{2} = 0

- 4 x^{2} - 4 x + 5 = 0

What are the solutions to the equation 2x^2+x+15=0 ?
The solutions to the equation 2x^2+x+15=0 are x=-1/4+i(sqrt(119))/4 ,x=-1/4-i(sqrt(119))/4
Find the zeros of 2x^2+x+15=0
The zeros of 2x^2+x+15=0 are x=-1/4+i(sqrt(119))/4 ,x=-1/4-i(sqrt(119))/4