What are the solutions to the equation 2x^2+3x+24=0 ?

The solutions to the equation 2x^2+3x+24=0 are x=-3/4+i(sqrt(183))/4 ,x=-3/4-i(sqrt(183))/4

Find the zeros of 2x^2+3x+24=0

The zeros of 2x^2+3x+24=0 are x=-3/4+i(sqrt(183))/4 ,x=-3/4-i(sqrt(183))/4

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2 x^{2} + 3 x + 24 = 0

x = - \frac{3}{4} + i \frac{183}{4}, x = - \frac{3}{4} - i \frac{183}{4}

Solution steps

2 x^{2} + 3 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 \cdot 24}{2 \cdot 2}

Simplify

3^{2} - 4 \cdot 2 \cdot 24 : 183 i

x_{1, 2} = \frac{- 3 \pm 183 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 183 i}{2 \cdot 2}, x_{2} = \frac{- 3 - 183 i}{2 \cdot 2}

x = \frac{- 3 + 183 i}{2 \cdot 2} : - \frac{3}{4} + i \frac{183}{4}

x = \frac{- 3 - 183 i}{2 \cdot 2} : - \frac{3}{4} - i \frac{183}{4}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{183}{4}, x = - \frac{3}{4} - i \frac{183}{4}

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y, x^{2} y^{2} - 4 x^{2} - 4 y^{2} = 0

- 4 x^{2} - 4 x + 5 = 0

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2 x^{2} - 5 x - 150 = 0

What are the solutions to the equation 2x^2+3x+24=0 ?
The solutions to the equation 2x^2+3x+24=0 are x=-3/4+i(sqrt(183))/4 ,x=-3/4-i(sqrt(183))/4
Find the zeros of 2x^2+3x+24=0
The zeros of 2x^2+3x+24=0 are x=-3/4+i(sqrt(183))/4 ,x=-3/4-i(sqrt(183))/4