What are the solutions to the equation 40=10x-x^2 ?

The solutions to the equation 40=10x-x^2 are x=5-sqrt(15)i,x=5+sqrt(15)i

Find the zeros of 40=10x-x^2

The zeros of 40=10x-x^2 are x=5-sqrt(15)i,x=5+sqrt(15)i

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40 = 10 x - x^{2}

x = 5 - 15 i, x = 5 + 15 i

Solution steps

40 = 10 x - x^{2}

Switch sides

10 x - x^{2} = 40

Move

40

to the left side

10 x - x^{2} - 40 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 10 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 40 )}{2 ( - 1 )}

Simplify

1 0^{2} - 4 (- 1) (- 40) : 215 i

x_{1, 2} = \frac{- 10 \pm 2 15 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 15 i}{2 ( - 1 )}, x_{2} = \frac{- 10 - 2 15 i}{2 ( - 1 )}

x = \frac{- 10 + 2 15 i}{2 ( - 1 )} : 5 - 15 i

x = \frac{- 10 - 2 15 i}{2 ( - 1 )} : 5 + 15 i

The solutions to the quadratic equation are:

x = 5 - 15 i, x = 5 + 15 i

4 x^{2} - 12 x - 9 + 3 = 0

1 0^{2} + 10 0^{2} = c^{2}

t, 5 t^{2} - 9 = 0

s^{2}

25 x^{2} + 5 x = 0

What are the solutions to the equation 40=10x-x^2 ?
The solutions to the equation 40=10x-x^2 are x=5-sqrt(15)i,x=5+sqrt(15)i
Find the zeros of 40=10x-x^2
The zeros of 40=10x-x^2 are x=5-sqrt(15)i,x=5+sqrt(15)i