What are the solutions to the equation s^2+20s+10=0 ?

The solutions to the equation s^2+20s+10=0 are s=-10+3sqrt(10),s=-10-3sqrt(10)

Find the zeros of s^2+20s+10=0

The zeros of s^2+20s+10=0 are s=-10+3sqrt(10),s=-10-3sqrt(10)

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s^{2} + 20 s + 10 = 0

s = - 10 + 310, s = - 10 - 310

Decimal Notation

s = - 0.51316 \dots, s = - 19.48683 \dots

Solution steps

s^{2} + 20 s + 10 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 10 = 610

s_{1, 2} = \frac{- 20 \pm 6 10}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 20 + 6 10}{2 \cdot 1}, s_{2} = \frac{- 20 - 6 10}{2 \cdot 1}

s = \frac{- 20 + 6 10}{2 \cdot 1} : - 10 + 310

s = \frac{- 20 - 6 10}{2 \cdot 1} : - 10 - 310

The solutions to the quadratic equation are:

s = - 10 + 310, s = - 10 - 310

(10 - y)^{2} + y^{2} = 68

x^{2} - 6 x + 9 = 2

2 s^{2} + s + 1 = 0

x^{2} + 8 + 3

0.81307831 x^{2} - 71.248 + 1600 = 0

What are the solutions to the equation s^2+20s+10=0 ?
The solutions to the equation s^2+20s+10=0 are s=-10+3sqrt(10),s=-10-3sqrt(10)
Find the zeros of s^2+20s+10=0
The zeros of s^2+20s+10=0 are s=-10+3sqrt(10),s=-10-3sqrt(10)