What are the solutions to the equation -22x^2+8=0 ?

The solutions to the equation -22x^2+8=0 are x= 2/(sqrt(11)),x=-2/(sqrt(11))

Find the zeros of -22x^2+8=0

The zeros of -22x^2+8=0 are x= 2/(sqrt(11)),x=-2/(sqrt(11))

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- 22 x^{2} + 8 = 0

x = \frac{2}{11}, x = - \frac{2}{11}

Decimal Notation

x = 0.60302 \dots, x = - 0.60302 \dots

Solution steps

- 22 x^{2} + 8 = 0

Move

8

to the right side

- 22 x^{2} = - 8

Divide both sides by

- 22

x^{2} = \frac{4}{11}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{11}, x = - \frac{4}{11}

\frac{4}{11} = \frac{2}{11}

- \frac{4}{11} = - \frac{2}{11}

x = \frac{2}{11}, x = - \frac{2}{11}

n^{2} - 18 n + 91 = 0

x, k x^{2} + 8 x + 2 k = 0

x, x^{2} - 4 x y - 2 y^{2} - 3 = 0

2 (x + 4) = - (2 x - 3)^{2}

0 = - 4.9 x^{2} + 30 x

What are the solutions to the equation -22x^2+8=0 ?
The solutions to the equation -22x^2+8=0 are x= 2/(sqrt(11)),x=-2/(sqrt(11))
Find the zeros of -22x^2+8=0
The zeros of -22x^2+8=0 are x= 2/(sqrt(11)),x=-2/(sqrt(11))