What are the solutions to the equation -1/3 x^2+2x-3=0 ?

The solutions to the equation -1/3 x^2+2x-3=0 are x=3

Find the zeros of -1/3 x^2+2x-3=0

The zeros of -1/3 x^2+2x-3=0 are x=3

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- \frac{1}{3} x^{2} + 2 x - 3 = 0

x = 3

Solution steps

- \frac{1}{3} x^{2} + 2 x - 3 = 0

Multiply both sides by

3

- x^{2} + 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 9 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 9) = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 ( - 1 )}

x = \frac{- 6}{2 ( - 1 )}

\frac{- 6}{2 ( - 1 )} = 3

x = 3

The solution to the quadratic equation is:

x = 3

x, y = 2 x^{2}

x^{2} - 1.3 x + 0.4 = 0

x^{2} - 11 x + 40 = 30

0 = - 16 t^{2} + 1454

6 x^{2} - 2 x + 8 = 0

What are the solutions to the equation -1/3 x^2+2x-3=0 ?
The solutions to the equation -1/3 x^2+2x-3=0 are x=3
Find the zeros of -1/3 x^2+2x-3=0
The zeros of -1/3 x^2+2x-3=0 are x=3