What are the solutions to the equation -4-2p^2=-40 ?

The solutions to the equation -4-2p^2=-40 are p=3sqrt(2),p=-3sqrt(2)

Find the zeros of -4-2p^2=-40

The zeros of -4-2p^2=-40 are p=3sqrt(2),p=-3sqrt(2)

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- 4 - 2 p^{2} = - 40

p = 32, p = - 32

Decimal Notation

p = 4.24264 \dots, p = - 4.24264 \dots

Solution steps

- 4 - 2 p^{2} = - 40

Move

4

to the right side

- 2 p^{2} = - 36

Divide both sides by

- 2

p^{2} = 18

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 18, p = - 18

18 = 32

- 18 = - 32

p = 32, p = - 32

s^{2} + 8 s + 100 = 0

96 - 80 x + 12 x^{2} = 0

a, - 4 a^{2} - 6 b^{2} b = 15 ab + 5 a^{2}

x + x^{2} - 100 = 17 x + 5

1 2^{2} = x (x + 7)

What are the solutions to the equation -4-2p^2=-40 ?
The solutions to the equation -4-2p^2=-40 are p=3sqrt(2),p=-3sqrt(2)
Find the zeros of -4-2p^2=-40
The zeros of -4-2p^2=-40 are p=3sqrt(2),p=-3sqrt(2)