What are the solutions to the equation 12^2=x(x+7) ?

The solutions to the equation 12^2=x(x+7) are x=9,x=-16

Find the zeros of 12^2=x(x+7)

The zeros of 12^2=x(x+7) are x=9,x=-16

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1 2^{2} = x (x + 7)

x = 9, x = - 16

Solution steps

1 2^{2} = x (x + 7)

Expand

1 2^{2} : 144

Expand

x (x + 7) : x^{2} + 7 x

144 = x^{2} + 7 x

Switch sides

x^{2} + 7 x = 144

Move

144

to the left side

x^{2} + 7 x - 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 144 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 144) = 25

x_{1, 2} = \frac{- 7 \pm 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 25}{2 \cdot 1}, x_{2} = \frac{- 7 - 25}{2 \cdot 1}

x = \frac{- 7 + 25}{2 \cdot 1} : 9

x = \frac{- 7 - 25}{2 \cdot 1} : - 16

The solutions to the quadratic equation are:

x = 9, x = - 16

(x - 8)^{2} + 9 = 25

16 a^{3} (3 x^{2} - 4 a^{2}) = 0

3 (x + 2)^{2} - 4 = 11

x (2 x - 4) - 100 = 4 (6 - x) - 17

2 x^{2} - 3 x - 42 = 2

What are the solutions to the equation 12^2=x(x+7) ?
The solutions to the equation 12^2=x(x+7) are x=9,x=-16
Find the zeros of 12^2=x(x+7)
The zeros of 12^2=x(x+7) are x=9,x=-16