What are the solutions to the equation (8t-7)(3t+5)=0 ?

The solutions to the equation (8t-7)(3t+5)=0 are t= 7/8 ,t=-5/3

Find the zeros of (8t-7)(3t+5)=0

The zeros of (8t-7)(3t+5)=0 are t= 7/8 ,t=-5/3

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(8 t - 7) (3 t + 5) = 0

t = \frac{7}{8}, t = - \frac{5}{3}

Decimal Notation

t = 0.875, t = - 1.66666 \dots

Solution steps

(8 t - 7) (3 t + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

8 t - 7 = 0 or 3 t + 5 = 0

Solve

8 t - 7 = 0 : t = \frac{7}{8}

Solve

3 t + 5 = 0 : t = - \frac{5}{3}

The solutions to the quadratic equation are:

t = \frac{7}{8}, t = - \frac{5}{3}

x^{2} = 4^{2} + 5^{2}

3 y^{2} - 5 - y^{2} = 3

- 0.125 x^{2} + 0.5 x + 5.5 = 0

(5 y + 6)^{2} = 24

9 x^{2} + 4 x = 1

What are the solutions to the equation (8t-7)(3t+5)=0 ?
The solutions to the equation (8t-7)(3t+5)=0 are t= 7/8 ,t=-5/3
Find the zeros of (8t-7)(3t+5)=0
The zeros of (8t-7)(3t+5)=0 are t= 7/8 ,t=-5/3