What are the solutions to the equation -0.125x^2+0.5x+5.5=0 ?

The solutions to the equation -0.125x^2+0.5x+5.5=0 are x=-2(2sqrt(3)-1),x=2(1+2sqrt(3))

Find the zeros of -0.125x^2+0.5x+5.5=0

The zeros of -0.125x^2+0.5x+5.5=0 are x=-2(2sqrt(3)-1),x=2(1+2sqrt(3))

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- 0.125 x^{2} + 0.5 x + 5.5 = 0

x = - 2 (23 - 1), x = 2 (1 + 23)

Decimal Notation

x = - 4.92820 \dots, x = 8.92820 \dots

Solution steps

- 0.125 x^{2} + 0.5 x + 5.5 = 0

Multiply both sides by

1000

- 125 x^{2} + 500 x + 5500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 500 \pm 50 0 ^{2} - 4 ( - 125 ) \cdot 5500}{2 ( - 125 )}

50 0^{2} - 4 (- 125) \cdot 5500 = 10003

x_{1, 2} = \frac{- 500 \pm 1000 3}{2 ( - 125 )}

Separate the solutions

x_{1} = \frac{- 500 + 1000 3}{2 ( - 125 )}, x_{2} = \frac{- 500 - 1000 3}{2 ( - 125 )}

x = \frac{- 500 + 1000 3}{2 ( - 125 )} : - 2 (23 - 1)

x = \frac{- 500 - 1000 3}{2 ( - 125 )} : 2 (1 + 23)

The solutions to the quadratic equation are:

x = - 2 (23 - 1), x = 2 (1 + 23)

(5 y + 6)^{2} = 24

9 x^{2} + 4 x = 1

x (x + 5) = 104

2 x^{2} + b x + 3 = 0

x^{2} + 5.71 \cdot 1 0^{- 12} x - 5.71 \cdot 1 0^{- 10} = 0

What are the solutions to the equation -0.125x^2+0.5x+5.5=0 ?
The solutions to the equation -0.125x^2+0.5x+5.5=0 are x=-2(2sqrt(3)-1),x=2(1+2sqrt(3))
Find the zeros of -0.125x^2+0.5x+5.5=0
The zeros of -0.125x^2+0.5x+5.5=0 are x=-2(2sqrt(3)-1),x=2(1+2sqrt(3))