What are the solutions to the equation 3x^2-8x+6=17 ?

The solutions to the equation 3x^2-8x+6=17 are x= 11/3 ,x=-1

Find the zeros of 3x^2-8x+6=17

The zeros of 3x^2-8x+6=17 are x= 11/3 ,x=-1

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3 x^{2} - 8 x + 6 = 17

x = \frac{11}{3}, x = - 1

Decimal Notation

x = 3.66666 \dots, x = - 1

Solution steps

3 x^{2} - 8 x + 6 = 17

Move

17

to the left side

3 x^{2} - 8 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 11 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 11) = 14

x_{1, 2} = \frac{- ( - 8 ) \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 14}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 14}{2 \cdot 3}

x = \frac{- ( - 8 ) + 14}{2 \cdot 3} : \frac{11}{3}

x = \frac{- ( - 8 ) - 14}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{11}{3}, x = - 1

1.6 \cdot 1 0^{- 19} \cdot 100 = \frac{1}{2} \cdot 1.67 \cdot 1 0^{- 27} v^{2}

- 2 z^{2} + 8 z - 8 = 0

- 16 t^{2} + 65.62 t - 98.43 = 0

(x - 3)^{2} + (x - 1)^{2} = 1

x, 5 x^{2} + 2 y^{2} - 10 x + 4 y + 7 = 0

What are the solutions to the equation 3x^2-8x+6=17 ?
The solutions to the equation 3x^2-8x+6=17 are x= 11/3 ,x=-1
Find the zeros of 3x^2-8x+6=17
The zeros of 3x^2-8x+6=17 are x= 11/3 ,x=-1