What are the solutions to the equation -2z^2+8z-8=0 ?

The solutions to the equation -2z^2+8z-8=0 are z=2

Find the zeros of -2z^2+8z-8=0

The zeros of -2z^2+8z-8=0 are z=2

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- 2 z^{2} + 8 z - 8 = 0

z = 2

Solution steps

- 2 z^{2} + 8 z - 8 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 8 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 8) = 0

z_{1, 2} = \frac{- 8 \pm 0}{2 ( - 2 )}

z = \frac{- 8}{2 ( - 2 )}

\frac{- 8}{2 ( - 2 )} = 2

z = 2

The solution to the quadratic equation is:

z = 2

- 16 t^{2} + 65.62 t - 98.43 = 0

(x - 3)^{2} + (x - 1)^{2} = 1

x, 5 x^{2} + 2 y^{2} - 10 x + 4 y + 7 = 0

5 p^{2} + 5 p + 4 = 0

x^{2} + 8 x + 2 = 0

What are the solutions to the equation -2z^2+8z-8=0 ?
The solutions to the equation -2z^2+8z-8=0 are z=2
Find the zeros of -2z^2+8z-8=0
The zeros of -2z^2+8z-8=0 are z=2