What are the solutions to the equation 5m^2-2m=6 ?

The solutions to the equation 5m^2-2m=6 are m=(1+sqrt(31))/5 ,m=(1-sqrt(31))/5

Find the zeros of 5m^2-2m=6

The zeros of 5m^2-2m=6 are m=(1+sqrt(31))/5 ,m=(1-sqrt(31))/5

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5 m^{2} - 2 m = 6

m = \frac{1 + 31}{5}, m = \frac{1 - 31}{5}

Decimal Notation

m = 1.31355 \dots, m = - 0.91355 \dots

Solution steps

5 m^{2} - 2 m = 6

Move

6

to the left side

5 m^{2} - 2 m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 6) = 231

m_{1, 2} = \frac{- ( - 2 ) \pm 2 31}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 31}{2 \cdot 5}, m_{2} = \frac{- ( - 2 ) - 2 31}{2 \cdot 5}

m = \frac{- ( - 2 ) + 2 31}{2 \cdot 5} : \frac{1 + 31}{5}

m = \frac{- ( - 2 ) - 2 31}{2 \cdot 5} : \frac{1 - 31}{5}

The solutions to the quadratic equation are:

m = \frac{1 + 31}{5}, m = \frac{1 - 31}{5}

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18 x^{2} + 6 x + 1 = 0

z^{2} - 11 z + 24 = 0

What are the solutions to the equation 5m^2-2m=6 ?
The solutions to the equation 5m^2-2m=6 are m=(1+sqrt(31))/5 ,m=(1-sqrt(31))/5
Find the zeros of 5m^2-2m=6
The zeros of 5m^2-2m=6 are m=(1+sqrt(31))/5 ,m=(1-sqrt(31))/5