What are the solutions to the equation v^2-v-6=0 ?

The solutions to the equation v^2-v-6=0 are v=3,v=-2

Find the zeros of v^2-v-6=0

The zeros of v^2-v-6=0 are v=3,v=-2

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v^{2} - v - 6 = 0

v = 3, v = - 2

Solution steps

v^{2} - v - 6 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

v_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, v_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

v = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

v = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

v = 3, v = - 2

- x^{2} = π - 2

x, t = x^{2}

12 a x^{2} + 8 a x + 12 b x + 4 b + 12 c = 0

- 7 x^{2} - 49 x = 0

x^{2} = - 2 x + 35

What are the solutions to the equation v^2-v-6=0 ?
The solutions to the equation v^2-v-6=0 are v=3,v=-2
Find the zeros of v^2-v-6=0
The zeros of v^2-v-6=0 are v=3,v=-2