What are the solutions to the equation v^2+10v+15=-6 ?

The solutions to the equation v^2+10v+15=-6 are v=-3,v=-7

Find the zeros of v^2+10v+15=-6

The zeros of v^2+10v+15=-6 are v=-3,v=-7

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v^{2} + 10 v + 15 = - 6

v = - 3, v = - 7

Solution steps

v^{2} + 10 v + 15 = - 6

Move

6

to the left side

v^{2} + 10 v + 21 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

v_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 10 + 4}{2 \cdot 1}, v_{2} = \frac{- 10 - 4}{2 \cdot 1}

v = \frac{- 10 + 4}{2 \cdot 1} : - 3

v = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

v = - 3, v = - 7

6 t^{2} - 5 t - 9 = 0

3 x^{2} = 49

3 x^{2} = 45

3 x^{2} = 42

0 = - x^{2} + 8 x + 20

What are the solutions to the equation v^2+10v+15=-6 ?
The solutions to the equation v^2+10v+15=-6 are v=-3,v=-7
Find the zeros of v^2+10v+15=-6
The zeros of v^2+10v+15=-6 are v=-3,v=-7