What are the solutions to the equation 6t^2-5t-9=0 ?

The solutions to the equation 6t^2-5t-9=0 are t=(5+sqrt(241))/(12),t=(5-sqrt(241))/(12)

Find the zeros of 6t^2-5t-9=0

The zeros of 6t^2-5t-9=0 are t=(5+sqrt(241))/(12),t=(5-sqrt(241))/(12)

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6 t^{2} - 5 t - 9 = 0

t = \frac{5 + 241}{12}, t = \frac{5 - 241}{12}

Decimal Notation

t = 1.71034 \dots, t = - 0.87701 \dots

Solution steps

6 t^{2} - 5 t - 9 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 9 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 9) = 241

t_{1, 2} = \frac{- ( - 5 ) \pm 241}{2 \cdot 6}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 241}{2 \cdot 6}, t_{2} = \frac{- ( - 5 ) - 241}{2 \cdot 6}

t = \frac{- ( - 5 ) + 241}{2 \cdot 6} : \frac{5 + 241}{12}

t = \frac{- ( - 5 ) - 241}{2 \cdot 6} : \frac{5 - 241}{12}

The solutions to the quadratic equation are:

t = \frac{5 + 241}{12}, t = \frac{5 - 241}{12}

3 x^{2} = 49

3 x^{2} = 45

3 x^{2} = 42

0 = - x^{2} + 8 x + 20

x^{2} - (n - 3) x - 3 n = 0

What are the solutions to the equation 6t^2-5t-9=0 ?
The solutions to the equation 6t^2-5t-9=0 are t=(5+sqrt(241))/(12),t=(5-sqrt(241))/(12)
Find the zeros of 6t^2-5t-9=0
The zeros of 6t^2-5t-9=0 are t=(5+sqrt(241))/(12),t=(5-sqrt(241))/(12)