What are the solutions to the equation 6x^2-9x=7 ?

The solutions to the equation 6x^2-9x=7 are x=(9+sqrt(249))/(12),x=(9-sqrt(249))/(12)

Find the zeros of 6x^2-9x=7

The zeros of 6x^2-9x=7 are x=(9+sqrt(249))/(12),x=(9-sqrt(249))/(12)

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6 x^{2} - 9 x = 7

x = \frac{9 + 249}{12}, x = \frac{9 - 249}{12}

Decimal Notation

x = 2.06497 \dots, x = - 0.56497 \dots

Solution steps

6 x^{2} - 9 x = 7

Move

7

to the left side

6 x^{2} - 9 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

(- 9)^{2} - 4 \cdot 6 (- 7) = 249

x_{1, 2} = \frac{- ( - 9 ) \pm 249}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 249}{2 \cdot 6}, x_{2} = \frac{- ( - 9 ) - 249}{2 \cdot 6}

x = \frac{- ( - 9 ) + 249}{2 \cdot 6} : \frac{9 + 249}{12}

x = \frac{- ( - 9 ) - 249}{2 \cdot 6} : \frac{9 - 249}{12}

The solutions to the quadratic equation are:

x = \frac{9 + 249}{12}, x = \frac{9 - 249}{12}

4 (\frac{2 y - 3}{2}) y - (\frac{2 y - 3}{2})^{2} - 3 (\frac{2 y - 3}{2}) = 0

14 y^{2} - 59 y + 12 = 0

2 x^{2} + 7 x = 1

0 = x^{2} + 2 x + 7

2 a^{2} = 25

What are the solutions to the equation 6x^2-9x=7 ?
The solutions to the equation 6x^2-9x=7 are x=(9+sqrt(249))/(12),x=(9-sqrt(249))/(12)
Find the zeros of 6x^2-9x=7
The zeros of 6x^2-9x=7 are x=(9+sqrt(249))/(12),x=(9-sqrt(249))/(12)