What are the solutions to the equation solvefor a,-2a^2+11ab-5b^2=0 ?

The solutions to the equation solvefor a,-2a^2+11ab-5b^2=0 are a= b/2 ,a=5b

Find the zeros of solvefor a,-2a^2+11ab-5b^2=0

The zeros of solvefor a,-2a^2+11ab-5b^2=0 are a= b/2 ,a=5b

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solve for

a, - 2 a^{2} + 11 ab - 5 b^{2} = 0

a = \frac{b}{2}, a = 5 b

Solution steps

- 2 a^{2} + 11 ab - 5 b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 a^{2} + 11 ba - 5 b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 11 b \pm ( 11 b ) ^{2} - 4 ( - 2 ) ( - 5 b ^{2} )}{2 ( - 2 )}

Simplify

(11 b)^{2} - 4 (- 2) (- 5 b^{2}) : 9 b

a_{1, 2} = \frac{- 11 b \pm 9 b}{2 ( - 2 )}

Separate the solutions

a_{1} = \frac{- 11 b + 9 b}{2 ( - 2 )}, a_{2} = \frac{- 11 b - 9 b}{2 ( - 2 )}

a = \frac{- 11 b + 9 b}{2 ( - 2 )} : \frac{b}{2}

a = \frac{- 11 b - 9 b}{2 ( - 2 )} : 5 b

The solutions to the quadratic equation are:

a = \frac{b}{2}, a = 5 b

9 x^{2} - 17 x = 2

x^{2} + 4 x + \frac{15}{4} = 0

g^{2} + 2 g - 15 = 0

5 r^{2} - 5 r = - 8

x, x^{2} y^{2} = - 1

What are the solutions to the equation solvefor a,-2a^2+11ab-5b^2=0 ?
The solutions to the equation solvefor a,-2a^2+11ab-5b^2=0 are a= b/2 ,a=5b
Find the zeros of solvefor a,-2a^2+11ab-5b^2=0
The zeros of solvefor a,-2a^2+11ab-5b^2=0 are a= b/2 ,a=5b