What are the solutions to the equation 25y^2-15y+9=0 ?

The solutions to the equation 25y^2-15y+9=0 are y= 3/10+i(3sqrt(3))/(10),y= 3/10-i(3sqrt(3))/(10)

Find the zeros of 25y^2-15y+9=0

The zeros of 25y^2-15y+9=0 are y= 3/10+i(3sqrt(3))/(10),y= 3/10-i(3sqrt(3))/(10)

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25 y^{2} - 15 y + 9 = 0

y = \frac{3}{10} + i \frac{3 3}{10}, y = \frac{3}{10} - i \frac{3 3}{10}

Solution steps

25 y^{2} - 15 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 25 \cdot 9}{2 \cdot 25}

Simplify

(- 15)^{2} - 4 \cdot 25 \cdot 9 : 153 i

y_{1, 2} = \frac{- ( - 15 ) \pm 15 3 i}{2 \cdot 25}

Separate the solutions

y_{1} = \frac{- ( - 15 ) + 15 3 i}{2 \cdot 25}, y_{2} = \frac{- ( - 15 ) - 15 3 i}{2 \cdot 25}

y = \frac{- ( - 15 ) + 15 3 i}{2 \cdot 25} : \frac{3}{10} + i \frac{3 3}{10}

y = \frac{- ( - 15 ) - 15 3 i}{2 \cdot 25} : \frac{3}{10} - i \frac{3 3}{10}

The solutions to the quadratic equation are:

y = \frac{3}{10} + i \frac{3 3}{10}, y = \frac{3}{10} - i \frac{3 3}{10}

x^{2} + 3 x - 6 = 0

x, x^{2} + y^{2} - 2 y + 6 = 0

x^{2} + 10 x + 2 = 0

b^{2} - 8 b - 9 = 0

1 8^{2} = (x + 2)^{2} + x

What are the solutions to the equation 25y^2-15y+9=0 ?
The solutions to the equation 25y^2-15y+9=0 are y= 3/10+i(3sqrt(3))/(10),y= 3/10-i(3sqrt(3))/(10)
Find the zeros of 25y^2-15y+9=0
The zeros of 25y^2-15y+9=0 are y= 3/10+i(3sqrt(3))/(10),y= 3/10-i(3sqrt(3))/(10)