What are the solutions to the equation 5m^2+26m+5=0 ?

The solutions to the equation 5m^2+26m+5=0 are m=-1/5 ,m=-5

Find the zeros of 5m^2+26m+5=0

The zeros of 5m^2+26m+5=0 are m=-1/5 ,m=-5

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5 m^{2} + 26 m + 5 = 0

m = - \frac{1}{5}, m = - 5

Decimal Notation

m = - 0.2, m = - 5

Solution steps

5 m^{2} + 26 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

2 6^{2} - 4 \cdot 5 \cdot 5 = 24

m_{1, 2} = \frac{- 26 \pm 24}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- 26 + 24}{2 \cdot 5}, m_{2} = \frac{- 26 - 24}{2 \cdot 5}

m = \frac{- 26 + 24}{2 \cdot 5} : - \frac{1}{5}

m = \frac{- 26 - 24}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

m = - \frac{1}{5}, m = - 5

2 x^{2} - x (- 2) + (- 2)^{2} = 8

x, 2 x^{2} - 10 x - 28 = 0

0 = 2 x^{2} - 4 x + 2

4 = 2 x^{2} - x + 3

2 t^{2} - 12 t + 16 = 0

What are the solutions to the equation 5m^2+26m+5=0 ?
The solutions to the equation 5m^2+26m+5=0 are m=-1/5 ,m=-5
Find the zeros of 5m^2+26m+5=0
The zeros of 5m^2+26m+5=0 are m=-1/5 ,m=-5