What are the solutions to the equation (2x-7)(x-1)=0 ?

The solutions to the equation (2x-7)(x-1)=0 are x= 7/2 ,x=1

Find the zeros of (2x-7)(x-1)=0

The zeros of (2x-7)(x-1)=0 are x= 7/2 ,x=1

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(2 x - 7) (x - 1) = 0

x = \frac{7}{2}, x = 1

Decimal Notation

x = 3.5, x = 1

Solution steps

(2 x - 7) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 7 = 0 or x - 1 = 0

Solve

2 x - 7 = 0 : x = \frac{7}{2}

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = 1

0 = - \frac{4.8}{2} + 8.4 - 2 + x

2 \cdot 1 0^{- 4}

2 5^{- \frac{1}{2}}

4 x^{2} + 4 x

(x + 1)^{2} = 2 (x - 1)^{2}

What are the solutions to the equation (2x-7)(x-1)=0 ?
The solutions to the equation (2x-7)(x-1)=0 are x= 7/2 ,x=1
Find the zeros of (2x-7)(x-1)=0
The zeros of (2x-7)(x-1)=0 are x= 7/2 ,x=1