What is the answer to 2x-(2x-(3x-1)/8)= 2/3 ((x+2)/6)-1/4 ?

The answer to 2x-(2x-(3x-1)/8)= 2/3 ((x+2)/6)-1/4 is x= 7/19

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2x-(2x-(3x-1)/8)= 2/3 ((x+2)/6)-1/4

2 x - (2 x - \frac{3 x - 1}{8}) = \frac{2}{3} (\frac{x + 2}{6}) - \frac{1}{4}

x = \frac{7}{19}

Solution steps

2 x - (2 x - \frac{3 x - 1}{8}) = \frac{2}{3} (\frac{x + 2}{6}) - \frac{1}{4}

Remove parentheses:

(a) = a

2 x - (2 x - \frac{3 x - 1}{8}) = \frac{2}{3} \cdot \frac{x + 2}{6} - \frac{1}{4}

\frac{2}{3} \cdot \frac{x + 2}{6} = \frac{x + 2}{9}

2 x - (2 x - \frac{3 x - 1}{8}) = \frac{x + 2}{9} - \frac{1}{4}

Expand

2 x - (2 x - \frac{3 x - 1}{8}) : \frac{3 x}{8} - \frac{1}{8}

Expand

\frac{x + 2}{9} - \frac{1}{4} : \frac{x}{9} + \frac{2}{9} - \frac{1}{4}

\frac{3 x}{8} - \frac{1}{8} = \frac{x}{9} + \frac{2}{9} - \frac{1}{4}

Multiply by LCM

27 x - 9 = 8 x - 2

Move

9

to the right side

27 x = 8 x + 7

Move

8 x

to the left side

19 x = 7

Divide both sides by

19

x = \frac{7}{19}

d, S = \frac{n}{2} [2 a + (n - 1) d]

4 x - 5 = 3

- 9 n + 19 n - 17 = 13

- 10 + 3 c + 1 = 3 + 5 c

s, v^{2} = u^{2} + 2 a s

What is the answer to 2x-(2x-(3x-1)/8)= 2/3 ((x+2)/6)-1/4 ?
The answer to 2x-(2x-(3x-1)/8)= 2/3 ((x+2)/6)-1/4 is x= 7/19
Solve for x: 2x-(2x-(3x-1)/8)= 2/3 ((x+2)/6)-1/4
The solution is x= 7/19