What are the solutions to the equation x^2+x+20=0 ?

The solutions to the equation x^2+x+20=0 are x=-1/2+i(sqrt(79))/2 ,x=-1/2-i(sqrt(79))/2

Find the zeros of x^2+x+20=0

The zeros of x^2+x+20=0 are x=-1/2+i(sqrt(79))/2 ,x=-1/2-i(sqrt(79))/2

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x^{2} + x + 20 = 0

x = - \frac{1}{2} + i \frac{79}{2}, x = - \frac{1}{2} - i \frac{79}{2}

Solution steps

x^{2} + x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 20 : 79 i

x_{1, 2} = \frac{- 1 \pm 79 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 79 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 79 i}{2 \cdot 1}

x = \frac{- 1 + 79 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{79}{2}

x = \frac{- 1 - 79 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{79}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{79}{2}, x = - \frac{1}{2} - i \frac{79}{2}

\frac{- 7 ( 1 + i )}{2 + i}

\frac{a ( 1 - 0. 2 ^{4} )}{1 - 0.2} = 671

- 4 (x + 2) > 3 x + 20

x^{2} - 5 x + 2 < 8

(- 25)^{\frac{1}{2}}

What are the solutions to the equation x^2+x+20=0 ?
The solutions to the equation x^2+x+20=0 are x=-1/2+i(sqrt(79))/2 ,x=-1/2-i(sqrt(79))/2
Find the zeros of x^2+x+20=0
The zeros of x^2+x+20=0 are x=-1/2+i(sqrt(79))/2 ,x=-1/2-i(sqrt(79))/2