What is the answer to (2x-1)(x+3)-1=2x^2+1 ?

The answer to (2x-1)(x+3)-1=2x^2+1 is x=1

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(2x-1)(x+3)-1=2x^2+1

(2 x - 1) (x + 3) - 1 = 2 x^{2} + 1

x = 1

Solution steps

(2 x - 1) (x + 3) - 1 = 2 x^{2} + 1

Expand

(2 x - 1) (x + 3) - 1 : 2 x^{2} + 5 x - 4

2 x^{2} + 5 x - 4 = 2 x^{2} + 1

Move

4

to the right side

2 x^{2} + 5 x = 2 x^{2} + 5

Move

2 x^{2}

to the left side

5 x = 5

Divide both sides by

5

x = 1

12 + \frac{3}{2} s - \frac{1}{2} - \frac{3}{4} s = \frac{5}{4} s

x, 4 x + 4 y = 8

y - (2 y + 1) = 8 - (3 y + 3)

\frac{1}{2} + x - \frac{x}{6} = \frac{1}{3} + 16 - \frac{2 x}{9}

x, 4 x - 5 y = 25

What is the answer to (2x-1)(x+3)-1=2x^2+1 ?
The answer to (2x-1)(x+3)-1=2x^2+1 is x=1
Solve for x: (2x-1)(x+3)-1=2x^2+1
The solution is x=1