What is the answer to 3x-1-(x-4)-[2(x-3)-3(1-2x)]=-x-2 ?

The answer to 3x-1-(x-4)-[2(x-3)-3(1-2x)]=-x-2 is x= 14/5

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3x-1-(x-4)-[2(x-3)-3(1-2x)]=-x-2

3 x - 1 - (x - 4) - [2 (x - 3) - 3 (1 - 2 x)] = - x - 2

x = \frac{14}{5}

Solution steps

3 x - 1 - (x - 4) - [2 (x - 3) - 3 (1 - 2 x)] = - x - 2

Expand

3 x - 1 - (x - 4) - (2 (x - 3) - 3 (1 - 2 x)) : - 6 x + 12

- 6 x + 12 = - x - 2

Move

12

to the right side

- 6 x = - x - 14

Move

x

to the left side

- 5 x = - 14

Divide both sides by

- 5

x = \frac{14}{5}

y, x = y - 3

h, S = 2 π r h + 2 π r^{2}

4 x - 2 = 8

f, f = {x + 1}

b, a = \frac{1}{2} (a + b) h

What is the answer to 3x-1-(x-4)-[2(x-3)-3(1-2x)]=-x-2 ?
The answer to 3x-1-(x-4)-[2(x-3)-3(1-2x)]=-x-2 is x= 14/5
Solve for x: 3x-1-(x-4)-[2(x-3)-3(1-2x)]=-x-2
The solution is x= 14/5