What are the solutions to the equation v^2-8v+16=0 ?

The solutions to the equation v^2-8v+16=0 are v=4

Find the zeros of v^2-8v+16=0

The zeros of v^2-8v+16=0 are v=4

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v^{2} - 8 v + 16 = 0

v = 4

Solution steps

v^{2} - 8 v + 16 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

v_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

v = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

v = 4

The solution to the quadratic equation is:

v = 4

(a - 3)^{2} = 6

\frac{3}{4} x^{2} + 1 = 31

9 a^{2} - 15 a + 4

2 r + (t + r)

4 (1 - 3 x) + 7 x = 9

What are the solutions to the equation v^2-8v+16=0 ?
The solutions to the equation v^2-8v+16=0 are v=4
Find the zeros of v^2-8v+16=0
The zeros of v^2-8v+16=0 are v=4