What are the solutions to the equation 3/4 x^2+1=31 ?

The solutions to the equation 3/4 x^2+1=31 are x=2sqrt(10),x=-2sqrt(10)

Find the zeros of 3/4 x^2+1=31

The zeros of 3/4 x^2+1=31 are x=2sqrt(10),x=-2sqrt(10)

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\frac{3}{4} x^{2} + 1 = 31

x = 210, x = - 210

Solution steps

\frac{3}{4} x^{2} + 1 = 31

Move

1

to the right side

\frac{3}{4} x^{2} = 30

Multiply both sides by

4

3 x^{2} = 120

Divide both sides by

3

x^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 40, x = - 40

40 = 210

- 40 = - 210

x = 210, x = - 210

9 a^{2} - 15 a + 4

2 r + (t + r)

4 (1 - 3 x) + 7 x = 9

(x - 5)^{2} = - 5

2 π r = 20

What are the solutions to the equation 3/4 x^2+1=31 ?
The solutions to the equation 3/4 x^2+1=31 are x=2sqrt(10),x=-2sqrt(10)
Find the zeros of 3/4 x^2+1=31
The zeros of 3/4 x^2+1=31 are x=2sqrt(10),x=-2sqrt(10)