What are the solutions to the equation a^2-54a-243=0 ?

The solutions to the equation a^2-54a-243=0 are a=9(3+2sqrt(3)),a=9(3-2sqrt(3))

Find the zeros of a^2-54a-243=0

The zeros of a^2-54a-243=0 are a=9(3+2sqrt(3)),a=9(3-2sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^{2} - 54 a - 243 = 0

a = 9 (3 + 23), a = 9 (3 - 23)

Decimal Notation

a = 58.17691 \dots, a = - 4.17691 \dots

Solution steps

a^{2} - 54 a - 243 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 54 ) \pm ( - 54 ) ^{2} - 4 \cdot 1 \cdot ( - 243 )}{2 \cdot 1}

(- 54)^{2} - 4 \cdot 1 \cdot (- 243) = 363

a_{1, 2} = \frac{- ( - 54 ) \pm 36 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 54 ) + 36 3}{2 \cdot 1}, a_{2} = \frac{- ( - 54 ) - 36 3}{2 \cdot 1}

a = \frac{- ( - 54 ) + 36 3}{2 \cdot 1} : 9 (3 + 23)

a = \frac{- ( - 54 ) - 36 3}{2 \cdot 1} : 9 (3 - 23)

The solutions to the quadratic equation are:

a = 9 (3 + 23), a = 9 (3 - 23)

18 m x - 6 m y + 54 n x - 18 n y

\frac{4}{5} (m - 1) - \frac{1}{5} m = 1

f = 4 (- 3)^{2} - 5

15 x^{2} - 22 x - 37 = 0

- 6 x < 21

What are the solutions to the equation a^2-54a-243=0 ?
The solutions to the equation a^2-54a-243=0 are a=9(3+2sqrt(3)),a=9(3-2sqrt(3))
Find the zeros of a^2-54a-243=0
The zeros of a^2-54a-243=0 are a=9(3+2sqrt(3)),a=9(3-2sqrt(3))