What are the solutions to the equation 15x^2-22x-37=0 ?

The solutions to the equation 15x^2-22x-37=0 are x= 37/15 ,x=-1

Find the zeros of 15x^2-22x-37=0

The zeros of 15x^2-22x-37=0 are x= 37/15 ,x=-1

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15 x^{2} - 22 x - 37 = 0

x = \frac{37}{15}, x = - 1

Decimal Notation

x = 2.46666 \dots, x = - 1

Solution steps

15 x^{2} - 22 x - 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 15 ( - 37 )}{2 \cdot 15}

(- 22)^{2} - 4 \cdot 15 (- 37) = 52

x_{1, 2} = \frac{- ( - 22 ) \pm 52}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 52}{2 \cdot 15}, x_{2} = \frac{- ( - 22 ) - 52}{2 \cdot 15}

x = \frac{- ( - 22 ) + 52}{2 \cdot 15} : \frac{37}{15}

x = \frac{- ( - 22 ) - 52}{2 \cdot 15} : - 1

The solutions to the quadratic equation are:

x = \frac{37}{15}, x = - 1

- 6 x < 21

8 y^{2} + 22 y + 15 = 0

- 11 - 5 a = 6 (5 a + 4)

(0.2 + x) (0.1 + x) = x

(x^{- \frac{1}{3}})^{2}

What are the solutions to the equation 15x^2-22x-37=0 ?
The solutions to the equation 15x^2-22x-37=0 are x= 37/15 ,x=-1
Find the zeros of 15x^2-22x-37=0
The zeros of 15x^2-22x-37=0 are x= 37/15 ,x=-1