What is the answer to |x^2+3x-15|=3 ?

The answer to |x^2+3x-15|=3 is x=-6\lor x=(-3-sqrt(57))/2 \lor x=(-3+sqrt(57))/2 \lor x=3

Solve for x: |x^2+3x-15|=3

The solution is x=-6\lor x=(-3-sqrt(57))/2 \lor x=(-3+sqrt(57))/2 \lor x=3

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x^{2} + 3 x - 15 = 3

x = - 6 or x = \frac{- 3 - 57}{2} or x = \frac{- 3 + 57}{2} or x = 3

Solution steps

x^{2} + 3 x - 15 = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 3 x - 15 = - 3 or x^{2} + 3 x - 15 = 3

x^{2} + 3 x - 15 = - 3 or x^{2} + 3 x - 15 = 3

(x = \frac{- 3 - 57}{2} or x = \frac{- 3 + 57}{2}) or (x = - 6 or x = 3)

x = - 6 or x = \frac{- 3 - 57}{2} or x = \frac{- 3 + 57}{2} or x = 3

e^{2 x} e^{2 x}

32 x^{2} + 16 x + 2 = 0

3 x^{2} - 14 x + 16

0.84 9^{2} - 0.15 1^{2}

3 w^{2} - 10 w = 8

What is the answer to |x^2+3x-15|=3 ?
The answer to |x^2+3x-15|=3 is x=-6\lor x=(-3-sqrt(57))/2 \lor x=(-3+sqrt(57))/2 \lor x=3
Solve for x: |x^2+3x-15|=3
The solution is x=-6\lor x=(-3-sqrt(57))/2 \lor x=(-3+sqrt(57))/2 \lor x=3