What are the solutions to the equation 32x^2+16x+2=0 ?

The solutions to the equation 32x^2+16x+2=0 are x=-1/4

Find the zeros of 32x^2+16x+2=0

The zeros of 32x^2+16x+2=0 are x=-1/4

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32 x^{2} + 16 x + 2 = 0

x = - \frac{1}{4}

Solution steps

32 x^{2} + 16 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 32 \cdot 2}{2 \cdot 32}

1 6^{2} - 4 \cdot 32 \cdot 2 = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 \cdot 32}

x = \frac{- 16}{2 \cdot 32}

\frac{- 16}{2 \cdot 32} = - \frac{1}{4}

x = - \frac{1}{4}

The solution to the quadratic equation is:

x = - \frac{1}{4}

3 x^{2} - 14 x + 16

0.84 9^{2} - 0.15 1^{2}

3 w^{2} - 10 w = 8

4 x^{2} - 5 x - 7 = 0

11 - 4 p \leq - 9

What are the solutions to the equation 32x^2+16x+2=0 ?
The solutions to the equation 32x^2+16x+2=0 are x=-1/4
Find the zeros of 32x^2+16x+2=0
The zeros of 32x^2+16x+2=0 are x=-1/4