What are the solutions to the equation x^2=5x-10 ?

The solutions to the equation x^2=5x-10 are x= 5/2+i(sqrt(15))/2 ,x= 5/2-i(sqrt(15))/2

Find the zeros of x^2=5x-10

The zeros of x^2=5x-10 are x= 5/2+i(sqrt(15))/2 ,x= 5/2-i(sqrt(15))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} = 5 x - 10

x = \frac{5}{2} + i \frac{15}{2}, x = \frac{5}{2} - i \frac{15}{2}

Solution steps

x^{2} = 5 x - 10

Move

10

to the left side

x^{2} + 10 = 5 x

Move

5 x

to the left side

x^{2} + 10 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 5 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 10 : 15 i

x_{1, 2} = \frac{- ( - 5 ) \pm 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 15 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 15 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 15 i}{2 \cdot 1} : \frac{5}{2} + i \frac{15}{2}

x = \frac{- ( - 5 ) - 15 i}{2 \cdot 1} : \frac{5}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{15}{2}, x = \frac{5}{2} - i \frac{15}{2}

- x^{2} - 4 x + 12

x^{4} - 81 y^{4}

48 x^{2} - 8 = 2 x - 22

- 4 + \frac{5}{3}

\frac{13}{5} - (\frac{1}{2} + \frac{1}{6})

What are the solutions to the equation x^2=5x-10 ?
The solutions to the equation x^2=5x-10 are x= 5/2+i(sqrt(15))/2 ,x= 5/2-i(sqrt(15))/2
Find the zeros of x^2=5x-10
The zeros of x^2=5x-10 are x= 5/2+i(sqrt(15))/2 ,x= 5/2-i(sqrt(15))/2