What are the solutions to the equation x^2-9x-15=-5 ?

The solutions to the equation x^2-9x-15=-5 are x=10,x=-1

Find the zeros of x^2-9x-15=-5

The zeros of x^2-9x-15=-5 are x=10,x=-1

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x^{2} - 9 x - 15 = - 5

x = 10, x = - 1

Solution steps

x^{2} - 9 x - 15 = - 5

Move

5

to the left side

x^{2} - 9 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 10) = 11

x_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 1}

x = \frac{- ( - 9 ) + 11}{2 \cdot 1} : 10

x = \frac{- ( - 9 ) - 11}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 10, x = - 1

5 + y = 12

7 x - 4 \leq 6

\frac{7}{12} - \frac{2}{5}

12 x^{2} + 4 x + 12 = 0

5 t^{2} - 6 t + 600 = 0

What are the solutions to the equation x^2-9x-15=-5 ?
The solutions to the equation x^2-9x-15=-5 are x=10,x=-1
Find the zeros of x^2-9x-15=-5
The zeros of x^2-9x-15=-5 are x=10,x=-1