What is the answer to solvefor x,[(y-1)] 2/4-[(x-3)] 2/9 =1 ?

The answer to solvefor x,[(y-1)] 2/4-[(x-3)] 2/9 =1 is x=-(-9y+15)/4

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solvefor x,[(y-1)] 2/4-[(x-3)] 2/9 =1

solve for

x, [(y - 1)] \frac{2}{4} - [(x - 3)] \frac{2}{9} = 1

x = - \frac{- 9 y + 15}{4}

Solution steps

[(y - 1)] \frac{2}{4} - [(x - 3)] \frac{2}{9} = 1

Move

[(y - 1)] \frac{2}{4}

to the right side

- [(x - 3)] \frac{2}{9} = 1 - \frac{y - 1}{2}

Expand

- ((x - 3)) \frac{2}{9} : - \frac{2}{9} x + \frac{2}{3}

Expand

1 - \frac{y - 1}{2} : 1 - \frac{y}{2} + \frac{1}{2}

- \frac{2}{9} x + \frac{2}{3} = 1 - \frac{y}{2} + \frac{1}{2}

Multiply both sides by

9

- 2 x + 6 = 9 - \frac{9 y}{2} + \frac{9}{2}

Move

6

to the right side

- 2 x = \frac{- 9 y + 9}{2} + 3

Divide both sides by

- 2

x = - \frac{- 9 y + 15}{4}

2 x - 3 = 3 x + 2

3 (5 x + 2) = 8 x + 20

x, 2 x + 3 y = - 9

8 - 2 x = 12

\frac{x + 2}{12} - \frac{2 x - 3}{9} = \frac{4 - 3 x}{18} + \frac{x}{6}

What is the answer to solvefor x,[(y-1)] 2/4-[(x-3)] 2/9 =1 ?
The answer to solvefor x,[(y-1)] 2/4-[(x-3)] 2/9 =1 is x=-(-9y+15)/4