What is (5ABC^9)/(15A^3B^3C) ?

The solution to (5ABC^9)/(15A^3B^3C) is (C^8)/(3A^2B^2)

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simplify (5ABC^9)/(15A^3B^3C)

simplify

\frac{5 A B C ^{9}}{15 A ^{3} B ^{3} C}

\frac{C ^{8}}{3 A ^{2} B ^{2}}

Solution steps

\frac{5 A B C ^{9}}{15 A ^{3} B ^{3} C}

Factor the number:

15 = 5 \cdot 3

= \frac{5 A B C ^{9}}{5 \cdot 3 A ^{3} B ^{3} C}

Cancel the common factor:

5

= \frac{A B C ^{9}}{3 A ^{3} B ^{3} C}

Simplify

\frac{C ^{9}}{C} : C^{8}

= \frac{A B C ^{8}}{3 A ^{3} B ^{3}}

Simplify

\frac{A}{A ^{3}} : \frac{1}{A ^{2}}

= \frac{B C ^{8}}{3 A ^{2} B ^{3}}

Simplify

\frac{B}{B ^{3}} : \frac{1}{B ^{2}}

= \frac{C ^{8}}{3 A ^{2} B ^{2}}

2 π x^{3} + 20 π x^{2} + 50 π x

4 ∣ 1 - 2 x ∣ - 8 = 28

- 16 t^{2} + 100 t + 85 = 0

7160 + 340

x (x^{\frac{1}{2}})

What is (5ABC^9)/(15A^3B^3C) ?
The solution to (5ABC^9)/(15A^3B^3C) is (C^8)/(3A^2B^2)