What is the answer to (4x-4)/7 =(x+3)/2 ?

The answer to (4x-4)/7 =(x+3)/2 is x=29

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(4x-4)/7 =(x+3)/2

\frac{4 x - 4}{7} = \frac{x + 3}{2}

x = 29

Solution steps

\frac{4 x - 4}{7} = \frac{x + 3}{2}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(4 x - 4) \cdot 2 = 7 (x + 3)

Expand

(4 x - 4) \cdot 2 : 8 x - 8

Expand

7 (x + 3) : 7 x + 21

8 x - 8 = 7 x + 21

Move

8

to the right side

8 x = 7 x + 29

Move

7 x

to the left side

x = 29

\frac{4 ^{- 0.001} - 1}{- 0.001}

3 (r - 2) = 18

- \frac{2}{5} + \frac{2}{3} w = - \frac{3}{2}

5 x^{2} + 4 x + 4 = 0

(x - 1)^{2} - 4

What is the answer to (4x-4)/7 =(x+3)/2 ?
The answer to (4x-4)/7 =(x+3)/2 is x=29
Solve for x: (4x-4)/7 =(x+3)/2
The solution is x=29