What are the solutions to the equation 5x^2+4x+4=0 ?

The solutions to the equation 5x^2+4x+4=0 are x=-2/5+i 4/5 ,x=-2/5-i 4/5

Find the zeros of 5x^2+4x+4=0

The zeros of 5x^2+4x+4=0 are x=-2/5+i 4/5 ,x=-2/5-i 4/5

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5 x^{2} + 4 x + 4 = 0

x = - \frac{2}{5} + i \frac{4}{5}, x = - \frac{2}{5} - i \frac{4}{5}

Solution steps

5 x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

Simplify

4^{2} - 4 \cdot 5 \cdot 4 : 8 i

x_{1, 2} = \frac{- 4 \pm 8 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 8 i}{2 \cdot 5}, x_{2} = \frac{- 4 - 8 i}{2 \cdot 5}

x = \frac{- 4 + 8 i}{2 \cdot 5} : - \frac{2}{5} + i \frac{4}{5}

x = \frac{- 4 - 8 i}{2 \cdot 5} : - \frac{2}{5} - i \frac{4}{5}

The solutions to the quadratic equation are:

x = - \frac{2}{5} + i \frac{4}{5}, x = - \frac{2}{5} - i \frac{4}{5}

(x - 1)^{2} - 4

b^{2} + 11 b - 12

lo g_{3} (2) = x

\frac{x}{5} + \frac{x}{8} = \frac{13}{40}

5 x^{2} + 7 x + 4 = 0

What are the solutions to the equation 5x^2+4x+4=0 ?
The solutions to the equation 5x^2+4x+4=0 are x=-2/5+i 4/5 ,x=-2/5-i 4/5
Find the zeros of 5x^2+4x+4=0
The zeros of 5x^2+4x+4=0 are x=-2/5+i 4/5 ,x=-2/5-i 4/5