What are the solutions to the equation 5x^2-9x+3=0 ?

The solutions to the equation 5x^2-9x+3=0 are x=(9+sqrt(21))/(10),x=(9-sqrt(21))/(10)

Find the zeros of 5x^2-9x+3=0

The zeros of 5x^2-9x+3=0 are x=(9+sqrt(21))/(10),x=(9-sqrt(21))/(10)

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5 x^{2} - 9 x + 3 = 0

x = \frac{9 + 21}{10}, x = \frac{9 - 21}{10}

Solution steps

5 x^{2} - 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

(- 9)^{2} - 4 \cdot 5 \cdot 3 = 21

x_{1, 2} = \frac{- ( - 9 ) \pm 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 21}{2 \cdot 5}, x_{2} = \frac{- ( - 9 ) - 21}{2 \cdot 5}

x = \frac{- ( - 9 ) + 21}{2 \cdot 5} : \frac{9 + 21}{10}

x = \frac{- ( - 9 ) - 21}{2 \cdot 5} : \frac{9 - 21}{10}

The solutions to the quadratic equation are:

x = \frac{9 + 21}{10}, x = \frac{9 - 21}{10}

ln (0)

\frac{1}{3} (2)^{2}

(4 x - 12 x^{2}) (16 y^{3} + 12 y^{2})

6 x^{2} + 7 x - 5 = 0

3 a + 6 = 21

What are the solutions to the equation 5x^2-9x+3=0 ?
The solutions to the equation 5x^2-9x+3=0 are x=(9+sqrt(21))/(10),x=(9-sqrt(21))/(10)
Find the zeros of 5x^2-9x+3=0
The zeros of 5x^2-9x+3=0 are x=(9+sqrt(21))/(10),x=(9-sqrt(21))/(10)