What are the solutions to the equation 6x^2+7x-5=0 ?

The solutions to the equation 6x^2+7x-5=0 are x= 1/2 ,x=-5/3

Find the zeros of 6x^2+7x-5=0

The zeros of 6x^2+7x-5=0 are x= 1/2 ,x=-5/3

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6 x^{2} + 7 x - 5 = 0

x = \frac{1}{2}, x = - \frac{5}{3}

Solution steps

6 x^{2} + 7 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

7^{2} - 4 \cdot 6 (- 5) = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 \cdot 6}, x_{2} = \frac{- 7 - 13}{2 \cdot 6}

x = \frac{- 7 + 13}{2 \cdot 6} : \frac{1}{2}

x = \frac{- 7 - 13}{2 \cdot 6} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{5}{3}

3 a + 6 = 21

64 x^{3} - 216 y^{3}

2 n^{- \frac{2}{3}} (n^{\frac{8}{3}} - 3 n^{\frac{5}{3}})

3 x^{2} + 39 = 18 x

2^{\frac{1}{3}} \cdot 4^{\frac{1}{3}}

What are the solutions to the equation 6x^2+7x-5=0 ?
The solutions to the equation 6x^2+7x-5=0 are x= 1/2 ,x=-5/3
Find the zeros of 6x^2+7x-5=0
The zeros of 6x^2+7x-5=0 are x= 1/2 ,x=-5/3