What is 2n^{-2/3}(n^{8/3}-3n^{5/3}) ?

The solution to 2n^{-2/3}(n^{8/3}-3n^{5/3}) is (2(n^{8/3}-3n^{5/3}))/(n^{2/3)}

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simplify 2n^{-2/3}(n^{8/3}-3n^{5/3})

simplify

2 n^{- \frac{2}{3}} (n^{\frac{8}{3}} - 3 n^{\frac{5}{3}})

\frac{2 ( n ^{\frac{8}{3}} - 3 n ^{\frac{5}{3}} )}{n ^{\frac{2}{3}}}

Solution steps

2 n^{- \frac{2}{3}} (n^{\frac{8}{3}} - 3 n^{\frac{5}{3}})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

n^{- \frac{2}{3}} = \frac{1}{n ^{\frac{2}{3}}}

= 2 \cdot \frac{1}{n ^{\frac{2}{3}}} (n^{\frac{8}{3}} - 3 n^{\frac{5}{3}})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 1 \cdot ( n ^{\frac{8}{3}} - 3 n ^{\frac{5}{3}} )}{n ^{\frac{2}{3}}}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2 ( n ^{\frac{8}{3}} - 3 n ^{\frac{5}{3}} )}{n ^{\frac{2}{3}}}

3 x^{2} + 39 = 18 x

2^{\frac{1}{3}} \cdot 4^{\frac{1}{3}}

12 = a^{2}

4 (2 x - 4) - 5 x + 4 = - 30

s^{2} - s - 12 = 0

What is 2n^{-2/3}(n^{8/3}-3n^{5/3}) ?
The solution to 2n^{-2/3}(n^{8/3}-3n^{5/3}) is (2(n^{8/3}-3n^{5/3}))/(n^{2/3)}