What is the answer to (3x-2)^2-(5x+2)^2=-(4x-2)^2 ?

The answer to (3x-2)^2-(5x+2)^2=-(4x-2)^2 is x= 1/12

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(3x-2)^2-(5x+2)^2=-(4x-2)^2

(3 x - 2)^{2} - (5 x + 2)^{2} = - (4 x - 2)^{2}

x = \frac{1}{12}

Decimal Notation

x = 0.08333 \dots

Solution steps

(3 x - 2)^{2} - (5 x + 2)^{2} = - (4 x - 2)^{2}

Expand

(3 x - 2)^{2} - (5 x + 2)^{2} : - 16 x^{2} - 32 x

Expand

- (4 x - 2)^{2} : - 16 x^{2} + 16 x - 4

- 16 x^{2} - 32 x = - 16 x^{2} + 16 x - 4

Subtract

- 16 x^{2} + 16 x

from both sides

- 16 x^{2} - 32 x - (- 16 x^{2} + 16 x) = - 16 x^{2} + 16 x - 4 - (- 16 x^{2} + 16 x)

Simplify

- 48 x = - 4

Divide both sides by

- 48

x = \frac{1}{12}

y, 4 x + y = 1

j, j (x) = \frac{4 x ^{2} - 3}{x ^{2} - 2 x}

8 (x - 3) + 14 = 2 (4 x + 5)

x, 5 x + y = 11

- 0.03 n = - 0.01 (2 n + 3)

What is the answer to (3x-2)^2-(5x+2)^2=-(4x-2)^2 ?
The answer to (3x-2)^2-(5x+2)^2=-(4x-2)^2 is x= 1/12
Solve for x: (3x-2)^2-(5x+2)^2=-(4x-2)^2
The solution is x= 1/12